練習題庫/gsat・難度 5若多項式恆等式 p(x−34)3+q(x−34)2+r(x−34)+5=−2(3−4x)3+3(3−4x)2+6(3−4x)+5p(x-\frac{3}{4})^3+q(x-\frac{3}{4})^2+r(x-\frac{3}{4})+5=-2(3-4x)^3+3(3-4x)^2+6(3-4x)+5p(x−43)3+q(x−43)2+r(x−43)+5=−2(3−4x)3+3(3−4x)2+6(3−4x)+5 成立，則 (p,q,r)(p,q,r)(p,q,r) 為何？(A)(128,48,−24)(128,48,-24)(128,48,−24)(B)(−128,48,24)(-128,48,24)(−128,48,24)(C)(8,−12,−24)(8,-12,-24)(8,−12,−24)(D)(132,316,−32)(\frac{1}{32},\frac{3}{16},-\frac{3}{2})(321,163,−23)登入後即可作答並查看完整詳解（每日免費 5 題）。